思路: 首先读取第一个表示颜色的字符串保存为结构体数组的第一个元素,个数为 1,结构体元素数个为1 然后每读取一个颜色字符串,就到结构体数组中寻找相同的字符串,如果找到,个数加1 如果没找到,在结构体中添加一个元素,个数为1,结构体元素个数加1 最后以结构体元素个数为标记,循环查找个数最大的一个元素,输出 #include <stdio.h> #include <string.h> #include <stdlib.h> #define LEN 20 struct color{ s...

/*Z -> A */ #include <stdio.h> #include <strings.h> /*某些编译器为: <string.h>*/ int main(void) { char ch[51]; int line, k, i = 1; scanf("%d", &amp;line); while(line--) { scanf("%s", ch); printf("String #%d\n", i++); for(k = 0; k < s...

#include <stdio.h> #include <math.h> int main(void) { int line, num, band, sum, i; char ch_l, ch_r; while(scanf("%d", &amp;line) != EOF) { if(line == 0) break; sum = 0; while(line--) { i = 0; scanf("%d%c%d%...

/*输入的第一行是一个整数，测试的数目。 *在每一行输入一个数字m,计算m^m 的最后一位 */ #include <stdio.h> int main(void) { int line, number, last, tmp; scanf("%d", &amp;line); while(line--) { last = 1; scanf("%d", &amp;number); tmp = number % 10; switch(tmp) ...

#include <stdio.h> int main(void) { int line, no_advertise, do_advertise, cost; scanf("%d", &amp;line); while(line--) { int tmp; scanf("%d %d %d", &amp;no_advertise, &amp;do_advertise, &amp;cost); tmp = do_advertise - cost - no_advertise; ...

/* 输入12行浮点数,计算平均数,保留2位小数*/ #include <stdio.h> #define MONTH 12 int main(void) { int month = MONTH; float balance, tmp = 0; while(month--) { scanf("%f", &amp;balance); tmp += balance; } printf("$%.2f\n", tmp / MONTH); return 0; }

#include <stdio.h> int main(void) { int n, m, tmp; while(scanf("%d %d", &amp;n, &amp;m) == 2) { if(n == -1 &amp;&amp; m == -1) break; while(m != 0) { tmp = n % m; n = m; m = tmp; } ...

#include <stdio.h> int main(void) { int s, n, tmp, sum; scanf("%d", &amp;n); while(n-- &amp;&amp; (scanf("%d", &amp;s) == 1)) { sum = 0; while(s--) { scanf("%d", &amp;tmp); sum += tmp; ...

#include <stdio.h> int main(void) { int a, b; while((scanf("%d %d", &amp;a, &amp;b) != EOF)) { printf("%d\n", a + b); printf("\n"); } return 0; }

#include <stdio.h> int main(void) { int n, tmp, sum; while((scanf("%d", &amp;n) != EOF)) { sum = 0; while(n--) { scanf("%d", &amp;tmp); sum += tmp; } printf("%d\n", sum); } return 0; }

#include <stdio.h> int main(void) { int s, n, tmp, sum; scanf("%d", &amp;n); while(n-- &amp;&amp; (scanf("%d", &amp;s) == 1)) { sum = 0; while(s--) { scanf("%d", &amp;tmp); sum += tmp; ...

#include <stdio.h> int main(void) { int n, tmp, sum; while((scanf("%d", &amp;n) == 1) &amp;&amp; n != 0) { sum = 0; while(n--) { scanf("%d", &amp;tmp); sum += tmp; } printf("%d\n", sum); } return 0...

/* a+b * 输入0 0 结束程序 */ #include <stdio.h> int main(void) { int a, b; while((scanf("%d %d", &amp;a, &amp;b)) &amp;&amp; a + b != 0) printf("%d\n", a + b); return 0; }

/*计算a + b * 输入包含一个整数N在第一行，然后N行跟进。 * 每行包含一个整数对A和B，用空格隔开，每行一个整数对。 */ #include <stdio.h> int main(void) { int a, b, n; scanf("%d", &amp;n); while(n > 0) { scanf("%d %d", &amp;a, &amp;b); printf("%d\n", a + b); n--; } return 0; ...

#include <stdio.h> int main(void) { int a, b; while((scanf("%d %d", &amp;a, &amp;b) != EOF)) printf("%d\n", a + b); return 0; }