下面代码可以产生5位随机数，如何将它转换为以下形式的随机数的数组。还请高手帮忙，请给出修改的全部代码！

产生以下：然后显示0到8这八个数字在一个3*3的格子，让每个数字随机如下图所示：
  +===+===+===+
  + 0 + 5 + 8 +
  + 7 + 4 + 3 +
  + 2 + 6 + 1 +
  +===+===+===+

下面是产生5个数的随机数，请高手帮忙修改：

using System;
using System.Collections.Generic;
using System.Text;

namespace ConsoleApplication9
{
    class Program
    {
        public static void Main(string[] args)
        {
            Random r = new Random();
            int[] number = new int[5];
            for (int i = 0; i < 5; i++)
            {

                number[i] = r.Next(0, 6);
                for (int j = 0; j < i; j++)
                {
                    if (number[i] == number[j])
                    {
                       
                        number[i] = r.Next(0, 6);
                        j = -1;
                    }
                }

            }

            for (int j = 0; j < 5; j++)
            {
                Console.Write("{0} ", number[j]);
            }
            string sss = Console.ReadLine();
        }
    }
}